1. **Problem Statement:** Find the median and standard deviation of the given data set. 2. **Median:** The median is the middle value when the data is ordered from least to greatest. If there is an odd number of data points, the median is the middle one. If even, it is the average of the two middle values. 3. **Standard Deviation:** It measures the amount of variation or dispersion in a set of values. The formula for the sample standard deviation is: $$s = \sqrt{\frac{1}{n-1} \sum_{i=1}^n (x_i - \bar{x})^2}$$ where $n$ is the number of data points, $x_i$ are the data points, and $\bar{x}$ is the mean. 4. **Steps to find Median:** - Sort the data. - Identify the middle value(s). - Calculate the median accordingly. 5. **Steps to find Standard Deviation:** - Calculate the mean $\bar{x} = \frac{1}{n} \sum_{i=1}^n x_i$. - Subtract the mean from each data point and square the result. - Sum all squared differences. - Divide by $n-1$. - Take the square root. 6. **Example:** Suppose the data is $[3, 7, 7, 19, 24]$. - Sorted data: $[3, 7, 7, 19, 24]$ (already sorted). - Median is the middle value: $7$. - Mean: $\bar{x} = \frac{3+7+7+19+24}{5} = \frac{60}{5} = 12$. - Squared differences: $(3-12)^2=81$, $(7-12)^2=25$, $(7-12)^2=25$, $(19-12)^2=49$, $(24-12)^2=144$. - Sum: $81+25+25+49+144=324$. - Divide by $n-1=4$: $\frac{324}{4}=81$. - Standard deviation: $s=\sqrt{81}=9$. **Final answers:** Median = $7$, Standard Deviation = $9$.