1. **State the problem:** We are given a data set of 13 distances to the nearest airport: 9, 10, 12, 12, 20, 21, 22, 23, 26, 32, 35, 35, 37. We need to find the median, lower quartile (Q1), and upper quartile (Q3). 2. **Recall definitions:** - The **median** is the middle value when data is ordered. - The **lower quartile (Q1)** is the median of the lower half of the data (below the median). - The **upper quartile (Q3)** is the median of the upper half of the data (above the median). 3. **Find the median:** Since there are 13 data points (odd number), the median is the value at position $\frac{13+1}{2} = 7$. The 7th value in the ordered list is 22. 4. **Find the lower quartile (Q1):** The lower half is the first 6 values: 9, 10, 12, 12, 20, 21. Since there are 6 values (even), Q1 is the average of the 3rd and 4th values: $$Q1 = \frac{12 + 12}{2} = 12$$ 5. **Find the upper quartile (Q3):** The upper half is the last 6 values: 23, 26, 32, 35, 35, 37. Q3 is the average of the 3rd and 4th values in this half: $$Q3 = \frac{32 + 35}{2} = 33.5$$ **Final answers:** (a) Median = 22 (b) Lower quartile = 12 (c) Upper quartile = 33.5