1. **State the problem:** We have the number of speeding tickets given each day in March: 56, 57, 43, 56, 87, 37, 76, 55, 29, 65, 84, 74, 46, 58, 61, 40, 43, 60, 51, 77, 53, 47, 50, 81, 61, 44, 55, 54, 76, 39, 77. 2. **Find the median:** - First, sort the data in ascending order: $$29, 37, 39, 40, 43, 43, 44, 46, 47, 50, 51, 53, 54, 55, 55, 56, 56, 57, 58, 60, 61, 61, 65, 74, 76, 76, 77, 77, 81, 84, 87$$ - There are 31 data points (days). - Median is the middle value, which is the 16th value (since $\frac{31+1}{2} = 16$). - The 16th value in the sorted list is 56. 3. **Answer for (a):** The median number of tickets given out on any day in March is **56**. 4. **Find the lower quartile (Q1):** - Q1 is the median of the lower half (first 15 values): $$29, 37, 39, 40, 43, 43, 44, 46, 47, 50, 51, 53, 54, 55, 55$$ - The median of these 15 values is the 8th value: 46. 5. **Compare the day with 43 tickets to Q1:** - Since 43 is less than 46, the day with 43 tickets is below the lower quartile. 6. **Answer for (b):** Yes, the day when 43 tickets were given ranks below the lower quartile. **Final answers:** - (a) Median = 56 - (b) 43 tickets is below the lower quartile (46)