1. **Problem statement:** We have a cumulative frequency table for the diameters of 60 oranges and need to (a) draw the cumulative frequency graph and (b) estimate the median diameter from the graph. 2. **Understanding cumulative frequency:** The cumulative frequency at a diameter $d$ is the total number of oranges with diameter less than or equal to $d$. 3. **Plotting the graph:** Plot points from the table: $(60,12), (70,42), (80,54), (90,57), (100,59), (110,60)$ on a graph with x-axis as diameter (50 to 110) and y-axis as cumulative frequency (0 to 60). 4. **Finding the median:** The median corresponds to the diameter at which half the oranges are counted. Since there are 60 oranges, half is $\frac{60}{2} = 30$. 5. **Estimating median from graph:** Locate cumulative frequency 30 on the y-axis. It lies between 12 at 60 mm and 42 at 70 mm. 6. **Interpolate to find median diameter:** Use linear interpolation between points $(60,12)$ and $(70,42)$: $$\text{Median diameter} = 60 + \frac{30 - 12}{42 - 12} \times (70 - 60) = 60 + \frac{18}{30} \times 10 = 60 + 6 = 66$$ 7. **Answer:** The estimated median diameter is approximately **66 mm**.