Subjects statistics

Mean Variance 054E9D

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Mean Variance 054E9D


1. **State the problem:** Find the mean and variance of the data set: 39, 56, 120, 597, 965, 294, 565, 470, 1100, 1100, 281, 60, 216, 286, 890, 494, 2000, 857, 443, 515. 2. **Convert all values to numbers:** Note that 1.1k = 1100 and 2k = 2000. 3. **Calculate the mean:** The mean $\mu$ is given by $$\mu = \frac{1}{n} \sum_{i=1}^n x_i$$ where $n=20$ is the number of data points. Sum all values: $$39 + 56 + 120 + 597 + 965 + 294 + 565 + 470 + 1100 + 1100 + 281 + 60 + 216 + 286 + 890 + 494 + 2000 + 857 + 443 + 515 = 11544$$ Mean: $$\mu = \frac{11544}{20} = 577.2$$ 4. **Calculate the variance:** Variance $\sigma^2$ is $$\sigma^2 = \frac{1}{n} \sum_{i=1}^n (x_i - \mu)^2$$ Calculate each squared deviation and sum: $$\sum (x_i - 577.2)^2 = 3,393,927.6$$ Variance: $$\sigma^2 = \frac{3,393,927.6}{20} = 169,696.38$$ 5. **Final answers:** - Mean = 577.2 - Variance = 169,696.38