1. The problem gives us a frequency table showing time intervals and how many students took that amount of time to answer a question. We need to calculate the mean time spent by a student. 2. Calculate the midpoint of each time interval because this will represent the typical time for each group: - For 3–7: midpoint = $\frac{3+7}{2} = 5$ - For 8–12: midpoint = $\frac{8+12}{2} = 10$ - For 13–17: midpoint = $\frac{13+17}{2} = 15$ - For 18–22: midpoint = $\frac{18+22}{2} = 20$ - For 23–27: midpoint = $\frac{23+27}{2} = 25$ 3. Multiply each midpoint by its frequency to find the total time contributed by each interval: - $5 \times 3 = 15$ - $10 \times 5 = 50$ - $15 \times 9 = 135$ - $20 \times 10 = 200$ - $25 \times 8 = 200$ 4. Add these products to find the total time: $$15 + 50 + 135 + 200 + 200 = 600$$ 5. Total number of students is 35 (sum of frequencies). The mean time is total time divided by total students: $$\text{Mean} = \frac{600}{35} \approx 17.14$$ 6. Rounding to 1 decimal place gives 17.1 minutes. Therefore, the mean time spent per student is 17.1 minutes, which corresponds to choice B.