Subjects statistics

Mean Score 4Aee6A

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Mean Score 4Aee6A


1. **Stating the problem:** Calculate the mean score of students in the literature quiz using the grouped frequency distribution table provided. 2. **Formula used:** The mean for grouped data is given by: $$\bar{x} = \frac{\sum f x}{\sum f}$$ where $f$ is the frequency and $x$ is the class mark. 3. **Important rules:** - Multiply each class mark $x$ by its corresponding frequency $f$ to get $fx$. - Sum all $fx$ values to get $\sum fx$. - Sum all frequencies $f$ to get $\sum f$. - Divide $\sum fx$ by $\sum f$ to find the mean. 4. **Intermediate work:** From the table: $$\sum fx = 64 + 143 + 266 + 357 + 360 + 276 + 78 + 29 = 1573$$ $$\sum f = 8 + 13 + 19 + 21 + 18 + 12 + 3 + 1 = 95$$ 5. **Calculation:** $$\bar{x} = \frac{1573}{95} \approx 16.56$$ 6. **Explanation:** The mean score of the students is approximately 16.56. This means on average, students scored about 16.56 in the literature quiz.