Mean Range Chart
1. **State the problem:** We have tensile test data for a plastic cord with subgroup size $n=4$ and $N=10$ samples. Each sample has a mean ($\bar{X}$) and range ($R$). We need to construct mean and range control charts to check if the process is in control.
2. **Given data:**
Sample No. | Mean ($\bar{X}$) | Range ($R$)
1 | 476 | 32
2 | 466 | 24
3 | 484 | 32
4 | 466 | 26
5 | 470 | 24
6 | 498 | 25
7 | 464 | 24
8 | 484 | 24
9 | 482 | 22
10 | 506 | 23
3. **Calculate overall mean of means ($\bar{\bar{X}}$):**
$$\bar{\bar{X}} = \frac{476 + 466 + 484 + 466 + 470 + 498 + 464 + 484 + 482 + 506}{10} = \frac{4796}{10} = 479.6$$
4. **Calculate overall mean of ranges ($\bar{R}$):**
$$\bar{R} = \frac{32 + 24 + 32 + 26 + 24 + 25 + 24 + 24 + 22 + 23}{10} = \frac{256}{10} = 25.6$$
5. **Determine control chart constants for subgroup size $n=4$:**
From standard tables:
$$A_2 = 0.729, \quad D_3 = 0, \quad D_4 = 2.282$$
6. **Calculate control limits for mean chart:**
$$UCL_{\bar{X}} = \bar{\bar{X}} + A_2 \times \bar{R} = 479.6 + 0.729 \times 25.6 = 479.6 + 18.6624 = 498.2624$$
$$LCL_{\bar{X}} = \bar{\bar{X}} - A_2 \times \bar{R} = 479.6 - 18.6624 = 460.9376$$
7. **Calculate control limits for range chart:**
$$UCL_R = D_4 \times \bar{R} = 2.282 \times 25.6 = 58.4192$$
$$LCL_R = D_3 \times \bar{R} = 0 \times 25.6 = 0$$
8. **Check if any points are out of control:**
- For mean chart, check if any $\bar{X}$ is outside $[460.94, 498.26]$.
- For range chart, check if any $R$ is outside $[0, 58.42]$.
From data:
- Mean values: 506 (sample 10) is above UCL (498.26), so out of control.
- Range values: all are within limits.
9. **Conclusion:** The process is not in control due to sample 10 mean exceeding the upper control limit. This indicates an assignable cause.
10. **Revise central line and control limits excluding out-of-control sample 10:**
- New $\bar{\bar{X}}$ excluding sample 10:
$$\frac{4796 - 506}{9} = \frac{4290}{9} = 476.67$$
- New $\bar{R}$ excluding sample 10:
$$\frac{256 - 23}{9} = \frac{233}{9} = 25.89$$
11. **Recalculate control limits:**
$$UCL_{\bar{X}} = 476.67 + 0.729 \times 25.89 = 476.67 + 18.87 = 495.54$$
$$LCL_{\bar{X}} = 476.67 - 18.87 = 457.80$$
$$UCL_R = 2.282 \times 25.89 = 59.06$$
$$LCL_R = 0$$
12. **Revised conclusion:**
With revised limits, all samples except sample 10 are within control limits. The process is now in control after removing the assignable cause.
**Final answer:** The process was initially out of control due to sample 10. After removing it and recalculating control limits, the process is in control.