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Mean Modal Class D26950

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Mean Modal Class D26950


1. **Problem Statement:** Find the mean electricity consumption and identify the modal class from the given frequency distribution. 2. **Given Data:** Class Intervals: 50–100, 100–150, 150–200, 200–250, 250–300, 300–350 Frequencies: 6, 14, 24, 30, 20, 6 3. **Formula for Mean:** $$\text{Mean} = \frac{\sum f_i x_i}{\sum f_i}$$ where $f_i$ is the frequency and $x_i$ is the class midpoint. 4. **Calculate Midpoints ($x_i$):** 50–100: $\frac{50+100}{2} = 75$ 100–150: $\frac{100+150}{2} = 125$ 150–200: $\frac{150+200}{2} = 175$ 200–250: $\frac{200+250}{2} = 225$ 250–300: $\frac{250+300}{2} = 275$ 300–350: $\frac{300+350}{2} = 325$ 5. **Calculate $f_i x_i$:** $6 \times 75 = 450$ $14 \times 125 = 1750$ $24 \times 175 = 4200$ $30 \times 225 = 6750$ $20 \times 275 = 5500$ $6 \times 325 = 1950$ 6. **Sum of frequencies:** $6 + 14 + 24 + 30 + 20 + 6 = 100$ 7. **Sum of $f_i x_i$:** $450 + 1750 + 4200 + 6750 + 5500 + 1950 = 20600$ 8. **Calculate Mean:** $$\text{Mean} = \frac{20600}{100} = 206$$ 9. **Identify Modal Class:** The modal class is the class with the highest frequency. Frequencies: 6, 14, 24, 30, 20, 6 Highest frequency is 30 corresponding to class 200–250. **Final Answer:** Mean electricity consumption = $206$ units Modal class = $200$–$250$ units