Lob Regression
1. **State the problem:** We have data on opponent's height (H) and unreturned lobs (L) from five matches. We want to find:
A. The dependent variable.
B. The least-squares regression equation.
C. The predicted number of unreturned lobs for an opponent 5.9 feet tall.
2. **Identify the dependent variable:** The dependent variable is the one we want to predict or explain. Here, it is the number of unreturned lobs (L) because it depends on the opponent's height.
3. **Calculate the least-squares regression line:** The regression line has the form $$L = a + bH$$ where $b$ is the slope and $a$ is the intercept.
Given data:
$$H = [5.0, 5.5, 6.0, 6.5, 5.0]$$
$$L = [9, 6, 3, 0, 7]$$
Calculate means:
$$\bar{H} = \frac{5.0 + 5.5 + 6.0 + 6.5 + 5.0}{5} = \frac{28.0}{5} = 5.6$$
$$\bar{L} = \frac{9 + 6 + 3 + 0 + 7}{5} = \frac{25}{5} = 5.0$$
Calculate slope $b$:
$$b = \frac{\sum (H_i - \bar{H})(L_i - \bar{L})}{\sum (H_i - \bar{H})^2}$$
Calculate numerator:
$$(5.0 - 5.6)(9 - 5) + (5.5 - 5.6)(6 - 5) + (6.0 - 5.6)(3 - 5) + (6.5 - 5.6)(0 - 5) + (5.0 - 5.6)(7 - 5)$$
$$= (-0.6)(4) + (-0.1)(1) + (0.4)(-2) + (0.9)(-5) + (-0.6)(2)$$
$$= -2.4 - 0.1 - 0.8 - 4.5 - 1.2 = -9.0$$
Calculate denominator:
$$(5.0 - 5.6)^2 + (5.5 - 5.6)^2 + (6.0 - 5.6)^2 + (6.5 - 5.6)^2 + (5.0 - 5.6)^2$$
$$= 0.36 + 0.01 + 0.16 + 0.81 + 0.36 = 1.7$$
So,
$$b = \frac{-9.0}{1.7} \approx -5.29$$
Calculate intercept $a$:
$$a = \bar{L} - b \bar{H} = 5.0 - (-5.29)(5.6) = 5.0 + 29.62 = 34.62$$
Thus, the least-squares regression equation is:
$$L = 34.62 - 5.29H$$
4. **Predict unreturned lobs for $H=5.9$ feet:**
$$L = 34.62 - 5.29 \times 5.9 = 34.62 - 31.21 = 3.41$$
So, the best estimate is approximately 3.41 unreturned lobs.
**Final answers:**
A. Dependent variable is the number of unreturned lobs (L).
B. Least-squares equation: $$L = 34.62 - 5.29H$$
C. Predicted unreturned lobs for opponent height 5.9 feet is approximately 3.41.