Linear Regression 4Aae3D
1. **State the problem:** We need to find the linear regression equation $y = mx + b$ for the data points $(4, -8)$, $(5, -14)$, $(7, -24)$, $(11, -43)$, and $(13, -60)$, rounding coefficients to the nearest hundredth.
2. **Formula for linear regression coefficients:**
- Slope: $$m = \frac{n\sum xy - \sum x \sum y}{n\sum x^2 - (\sum x)^2}$$
- Intercept: $$b = \frac{\sum y - m \sum x}{n}$$
where $n$ is the number of points.
3. **Calculate sums:**
- $n = 5$
- $\sum x = 4 + 5 + 7 + 11 + 13 = 40$
- $\sum y = -8 - 14 - 24 - 43 - 60 = -149$
- $\sum x^2 = 4^2 + 5^2 + 7^2 + 11^2 + 13^2 = 16 + 25 + 49 + 121 + 169 = 380$
- $\sum xy = (4)(-8) + (5)(-14) + (7)(-24) + (11)(-43) + (13)(-60) = -32 - 70 - 168 - 473 - 780 = -1523$
4. **Calculate slope $m$:**
$$m = \frac{5(-1523) - 40(-149)}{5(380) - 40^2} = \frac{-7615 + 5960}{1900 - 1600} = \frac{-1655}{300} = -5.52$$
5. **Calculate intercept $b$:**
$$b = \frac{-149 - (-5.52)(40)}{5} = \frac{-149 + 220.8}{5} = \frac{71.8}{5} = 14.36$$
6. **Write the regression equation:**
$$y = -5.52x + 14.36$$
This is the linear regression equation rounded to the nearest hundredth.