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Line Best Fit

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Line Best Fit


1. The problem asks us to find the equation of the line of best fit for the scatter plot relating time spent studying ($x$) to quiz score ($y$), and then use that equation to predict the quiz score for 60 minutes of study. 2. From the scatter plot, we observe a positive linear trend. We approximate two points on the line of best fit to find its equation. For example, approximate points: $(10, 40)$ and $(90, 90)$. 3. Calculate the slope $m$ of the line: $$m = \frac{90 - 40}{90 - 10} = \frac{50}{80} = 0.625$$ 4. Use point-slope form with point $(10, 40)$: $$y - 40 = 0.625(x - 10)$$ 5. Simplify to slope-intercept form: $$y = 0.625x - 6.25 + 40 = 0.625x + 33.75$$ 6. The approximate equation of the line of best fit is: $$y = 0.63x + 33.75$$ 7. To predict the quiz score for a student who studied 60 minutes, substitute $x=60$: $$y = 0.63(60) + 33.75 = 37.8 + 33.75 = 71.55$$ 8. The predicted quiz score is approximately $71.55$. Final answers: (a) $y = 0.63x + 33.75$ (b) Predicted quiz score for 60 minutes: $71.55$