1. **Problem Statement:** Predict the final grade for a student who misses five days using the least-squares regression line. 2. **Given Data:** Number of absences $x$: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 Final grade $y$: 88.8, 85.9, 82.9, 80.4, 77.4, 73.0, 63.4, 67.9, 64.9, 62.0 3. **Regression Line Formula:** The least-squares regression line is generally given by: $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 4. **Using the given prediction for zero absences:** For $x=0$, predicted $y=94.38$, so $b=94.38$. 5. **Calculate slope $m$ using two points:** Use points $(0,94.38)$ and $(5,73.0)$ (actual data for 5 absences): $$m = \frac{73.0 - 94.38}{5 - 0} = \frac{-21.38}{5} = -4.276$$ 6. **Regression line equation:** $$y = -4.276x + 94.38$$ 7. **Predict final grade for $x=5$ absences:** $$y = -4.276 \times 5 + 94.38 = -21.38 + 94.38 = 73.0$$ **Final answer:** The predicted final grade for a student who misses five days is **73.0**.