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Frequency Distribution F907D4

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Frequency Distribution F907D4


1. **Problem Statement:** We have weekly physical training hours for 30 soldiers: 3, 4, 5, 6, 7, 8, 3, 4, 5, 6, 7, 8, 4, 5, 6, 7, 8, 5, 6, 7, 8, 4, 5, 6, 7, 3, 4, 5, 6, 7. We need to construct a frequency distribution table using appropriate class intervals. 2. **Step 1: Identify the range of data.** - Minimum value $= 3$ - Maximum value $= 8$ - Range $= 8 - 3 = 5$ 3. **Step 2: Decide class intervals.** - Since the data ranges from 3 to 8, we can use class intervals of width 1 for clarity. - Class intervals: $[3,4), [4,5), [5,6), [6,7), [7,8],$ but since data includes 8, we include 8 in the last interval. 4. **Step 3: Count frequencies for each class interval.** - $[3,4)$ includes values 3 only. - $[4,5)$ includes values 4 only. - $[5,6)$ includes values 5 only. - $[6,7)$ includes values 6 only. - $[7,8]$ includes values 7 and 8. 5. **Step 4: Tally the frequencies.** - Count of 3: 3 times - Count of 4: 6 times - Count of 5: 6 times - Count of 6: 5 times - Count of 7: 6 times - Count of 8: 4 times 6. **Step 5: Construct the frequency distribution table:** | Class Interval | Frequency | |----------------|-----------| | 3 - 3.99 | 3 | | 4 - 4.99 | 6 | | 5 - 5.99 | 6 | | 6 - 6.99 | 5 | | 7 - 8 | 10 | Note: The last class interval combines 7 and 8 because 8 is the maximum value. **Final answer:** The frequency distribution table is as above.