Frequency Distribution F907D4
1. **Problem Statement:** We have weekly physical training hours for 30 soldiers: 3, 4, 5, 6, 7, 8, 3, 4, 5, 6, 7, 8, 4, 5, 6, 7, 8, 5, 6, 7, 8, 4, 5, 6, 7, 3, 4, 5, 6, 7. We need to construct a frequency distribution table using appropriate class intervals.
2. **Step 1: Identify the range of data.**
- Minimum value $= 3$
- Maximum value $= 8$
- Range $= 8 - 3 = 5$
3. **Step 2: Decide class intervals.**
- Since the data ranges from 3 to 8, we can use class intervals of width 1 for clarity.
- Class intervals: $[3,4), [4,5), [5,6), [6,7), [7,8],$ but since data includes 8, we include 8 in the last interval.
4. **Step 3: Count frequencies for each class interval.**
- $[3,4)$ includes values 3 only.
- $[4,5)$ includes values 4 only.
- $[5,6)$ includes values 5 only.
- $[6,7)$ includes values 6 only.
- $[7,8]$ includes values 7 and 8.
5. **Step 4: Tally the frequencies.**
- Count of 3: 3 times
- Count of 4: 6 times
- Count of 5: 6 times
- Count of 6: 5 times
- Count of 7: 6 times
- Count of 8: 4 times
6. **Step 5: Construct the frequency distribution table:**
| Class Interval | Frequency |
|----------------|-----------|
| 3 - 3.99 | 3 |
| 4 - 4.99 | 6 |
| 5 - 5.99 | 6 |
| 6 - 6.99 | 5 |
| 7 - 8 | 10 |
Note: The last class interval combines 7 and 8 because 8 is the maximum value.
**Final answer:** The frequency distribution table is as above.