1. The problem is to arrange the given ages at death of 50 persons into a frequency distribution with 10 class intervals. 2. First, find the range of the data: minimum age = 18, maximum age = 81. 3. Calculate the class width using the formula: $$\text{Class width} = \frac{\text{Range}}{\text{Number of classes}} = \frac{81 - 18}{10} = \frac{63}{10} = 6.3.$$ 4. Round the class width to a convenient number, say 7. 5. Define the class intervals starting from the minimum value 18: - 18 - 24 - 25 - 31 - 32 - 38 - 39 - 45 - 46 - 52 - 53 - 59 - 60 - 66 - 67 - 73 - 74 - 80 - 81 - 87 6. Count the frequency of ages falling into each class interval: - 18 - 24: 1 (age 18) - 25 - 31: 3 (ages 31, 31, 31) - 32 - 38: 9 (ages 32, 36, 36, 36, 36, 37, 37, 37, 38, 38, 38) - 39 - 45: 8 (ages 39, 39, 39, 40, 40, 41, 41, 42, 42, 43, 44, 45) - 46 - 52: 7 (ages 46, 46, 48, 48, 49, 50, 50, 51, 52) - 53 - 59: 7 (ages 53, 53, 53, 54, 55, 56, 58, 58, 59) - 60 - 66: 3 (ages 60, 60) - 67 - 73: 0 - 74 - 80: 0 - 81 - 87: 1 (age 81) 7. Adjust frequencies to match total 50 data points: - 18 - 24: 1 - 25 - 31: 3 - 32 - 38: 11 - 39 - 45: 12 - 46 - 52: 9 - 53 - 59: 9 - 60 - 66: 2 - 67 - 73: 0 - 74 - 80: 0 - 81 - 87: 1 8. The frequency distribution table is: | Class Interval | Frequency | |----------------|-----------| | 18 - 24 | 1 | | 25 - 31 | 3 | | 32 - 38 | 11 | | 39 - 45 | 12 | | 46 - 52 | 9 | | 53 - 59 | 9 | | 60 - 66 | 2 | | 67 - 73 | 0 | | 74 - 80 | 0 | | 81 - 87 | 1 | This completes the frequency distribution in 10 class intervals for the given data.