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Frequency Distribution Aaf66E

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Frequency Distribution Aaf66E


1. **Problem:** Construct a frequency distribution table using appropriate class intervals for the weekly physical training hours of 30 soldiers: 3, 4, 5, 6, 7, 8, 3, 4, 5, 6, 7, 8, 4, 5, 6, 7, 8, 5, 6, 7, 8, 4, 5, 6, 7, 3, 4, 5, 6, 7. 2. **Formula and Rules:** - Frequency distribution groups data into classes (intervals) and counts how many data points fall into each class. - Class intervals should be mutually exclusive and exhaustive. - The range is from minimum to maximum data values. 3. **Step-by-step solution:** - Identify minimum and maximum values: min = 3, max = 8. - Choose class intervals that cover all data points. Since data are integers from 3 to 8, use intervals: 3-3, 4-4, 5-5, 6-6, 7-7, 8-8 (each class is a single value). - Count frequencies: - 3 appears: count how many times 3 occurs. - 4 appears: count how many times 4 occurs. - 5 appears: count how many times 5 occurs. - 6 appears: count how many times 6 occurs. - 7 appears: count how many times 7 occurs. - 8 appears: count how many times 8 occurs. 4. **Counting frequencies:** - 3: appears 3 times (positions 1,7,26) - 4: appears 5 times (positions 2,8,13,22,27) - 5: appears 6 times (positions 3,9,14,18,23,28) - 6: appears 6 times (positions 4,10,15,19,24,29) - 7: appears 7 times (positions 5,11,16,20,25,30) - 8: appears 3 times (positions 6,12,17) 5. **Frequency distribution table:** | Class Interval | Frequency | |----------------|-----------| | 3 | 3 | | 4 | 5 | | 5 | 6 | | 6 | 6 | | 7 | 7 | | 8 | 3 | This table shows how many soldiers trained for each hour value per week. **Final answer:** The frequency distribution table is as above.