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Five Number Summary C7A901

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Five Number Summary C7A901


1. **Restate the problem:** We need to correctly find the upper quartile (Q3) for the data set with frequencies: 25(4), 26(1), 27(4), 28(3), 29(2), 30(3). 2. **Recall the ordered data set:** $$25, 25, 25, 25, 26, 27, 27, 27, 27, 28, 28, 28, 29, 29, 30, 30, 30$$ 3. **Total data points:** $17$ 4. **Median position:** $\frac{17+1}{2} = 9$th data point, which is $27$. 5. **Lower half data (below median):** First 8 data points: $$25, 25, 25, 25, 26, 27, 27, 27$$ 6. **Upper half data (above median):** Last 8 data points: $$28, 28, 28, 29, 29, 30, 30, 30$$ 7. **Find Q3 (median of upper half):** Number of points in upper half = 8, so median position is $\frac{8+1}{2} = 4.5$. 8. **Q3 is average of 4th and 5th data points in upper half:** 4th data point = $29$, 5th data point = $29$ 9. **Calculate Q3:** $$Q3 = \frac{29 + 29}{2} = 29$$ **Final corrected five number summary:** - Minimum: 25 - Lower quartile (Q1): 25.5 - Median: 27 - Upper quartile (Q3): 29 - Maximum: 30