Employee Time Stats 1F59Ec
1. **Problem Statement:** We have a sample of times (in seconds) taken by employees to complete a task: 63, 229, 165, 77, 49, 74, 67, 59, 66, 102, 81, 72, 59, 74, 61, 82, 48, 70, 86.
2. **Stem-and-Leaf Plot:**
- Stem represents the tens digit, leaf the units digit.
- Sorted data: 48, 49, 59, 59, 61, 63, 66, 67, 70, 72, 74, 74, 77, 81, 82, 86, 102, 165, 229.
- Plot:
4 | 8 9
5 | 9 9
6 | 1 3 6 7
7 | 0 2 4 4 7
8 | 1 2 6
10 | 2
16 | 5
22 | 9
- From this, we see most data is between 40 and 90 seconds, with some high outliers (102, 165, 229).
3. **Measures of Central Tendency and Quartiles:**
- Mean: $\frac{63+229+165+77+49+74+67+59+66+102+81+72+59+74+61+82+48+70+86}{19} = \frac{1594}{19} \approx 83.89$
- Mode: 59 and 74 (both appear twice)
- Median: Middle value of sorted data (19 values), 10th value = 72
- Quartiles:
- Q1 (25th percentile): median of first 9 values = 61
- Q3 (75th percentile): median of last 9 values = 82
4. **80th Percentile:**
- Position = $0.8 \times (19+1) = 16$th value in sorted data = 86
- Meaning: 80% of employees took 86 seconds or less to complete the task.
5. **Variance and Standard Deviation:**
- Variance $s^2 = \frac{1}{n-1} \sum (x_i - \bar{x})^2$
- Calculate squared deviations, sum them, divide by 18:
Sum of squared deviations $\approx 20494.32$
Variance $= \frac{20494.32}{18} \approx 1138.57$
- Standard deviation $s = \sqrt{1138.57} \approx 33.74$
6. **Coefficient of Variation (CV):**
- $CV = \frac{s}{\bar{x}} = \frac{33.74}{83.89} \approx 0.402$
- CV measures relative variability; important to compare variability between datasets with different units or means.
7. **Box-Plot Construction:**
- Minimum: 48
- Q1: 61
- Median: 72
- Q3: 82
- Maximum: 229
- Outliers: Values > $Q3 + 1.5 \times IQR = 82 + 1.5 \times (82-61) = 82 + 31.5 = 113.5$
- Outliers are 165 and 229.
- Box-plot shows most data concentrated between 48 and 82 with some high outliers.
8. **Skewness and Outliers:**
- Data is right-skewed due to high outliers (165, 229).
- Outliers identified above.
Final answers:
- Mean $\approx 83.89$
- Mode = 59, 74
- Median = 72
- Q1 = 61, Q3 = 82
- 80th percentile = 86
- Variance $\approx 1138.57$
- Standard deviation $\approx 33.74$
- Coefficient of variation $\approx 0.402$
- Data is right-skewed with outliers at 165 and 229.