1. **Problem statement:** A family recorded their monthly electricity bills over 6 months: 1200, 1250, 1300, 1280, 5000, 1270. We are asked to find (a) the mean and median of the bills, and (b) determine which value better represents their typical electricity bill with explanation. 2. **Calculate the mean:** The mean is the average of all values. Sum all bills: $$1200 + 1250 + 1300 + 1280 + 5000 + 1270 = 12300$$ Number of months = 6 Mean = $$\frac{12300}{6} = 2050$$ BDT 3. **Calculate the median:** The median is the middle value when data are ordered. Order the bills: $$1200, 1250, 1270, 1280, 1300, 5000$$ Since there are 6 numbers (even), median = average of 3rd and 4th values: $$\frac{1270 + 1280}{2} = \frac{2550}{2} = 1275$$ BDT 4. **Interpretation of mean vs median:** The mean is 2050, which is much higher than most bills because of the large value 5000, which is an outlier. The median is 1275, which falls between the typical values excluding the outlier. Thus, the median gives a better understanding of the family's typical monthly electricity bill because it is not skewed by the unusually high bill of 5000. **Final answers:** - Mean bill = 2050 BDT - Median bill = 1275 BDT - Median better represents the typical bill due to the presence of an outlier.