1. **State the problem:** Given a set of values $x$ with mean $\bar{x} = 9$, and the corresponding deviations $(x - \bar{x})$ and squared deviations $(x - \bar{x})^2$, verify the computations and understand the significance of the total squared deviations. 2. **Verify deviations:** For each value $x$, compute $x - \bar{x}$. For example, for $x=22$, $22 - 9 = 13$. This matches the table. Check several to confirm correctness. 3. **Verify squared deviations:** Square each deviation, e.g., $13^2 = 169$, $8^2 = 64$, and so forth. The table's squared values match the calculations. 4. **Sum of deviations:** The sum of all deviations $(x - \bar{x})$ is $0$, which confirms that $\bar{x}=9$ is correctly computed as the mean. 5. **Sum of squared deviations:** The total of squared deviations is $474$. This is the numerator part of variance calculation (before dividing by $n-1$ for sample variance or $n$ for population variance). 6. **Interpretation:** The squared deviations measure how spread out the data points are around the mean. The total $474$ represents the aggregate squared distance from the mean. **Final answer:** The computations for deviations and squared deviations are correct, with a sum of squared deviations equal to $474$. This sum is essential for calculating the variance and standard deviation.