1. **Calculate the range of the data recorded.** The data marks of 21 learners are: 15, 7, 11, 7, 13, 4, 8, 9, 3, 7, 25, 7, 6, 10, 8, 9, 23, 19, 7, 5, 7. Step 1: Identify the minimum and maximum marks. Minimum = $3$ (lowest mark) Maximum = $25$ (highest mark) Step 2: Calculate the range using the formula: $$\text{Range} = \text{Maximum} - \text{Minimum} = 25 - 3 = 22$$ 2. **Calculate the mean, median, and mode.** Step 1: Calculate the mean (average). Sum all marks: $15 + 7 + 11 + 7 + 13 + 4 + 8 + 9 + 3 + 7 + 25 + 7 + 6 + 10 + 8 + 9 + 23 + 19 + 7 + 5 + 7 = 196$ Number of learners = 21 Mean = $\frac{196}{21} = \frac{196}{21} = 9.33$ (rounded to 2 decimal places) Step 2: Calculate the median. Arrange the data in ascending order: 3, 4, 5, 6, 7, 7, 7, 7, 7, 7, 7, 8, 8, 9, 9, 10, 11, 13, 15, 19, 23, 25 (Note: There are 22 numbers listed here; recount and check original data.) Recount the data points: 3,4,5,6,7,7,7,7,7,7,7 (7 times), 8,8,9,9,10,11,13,15,19,23,25 Actually, original data has 21 learners, count 7s carefully. There are exactly 8 sevens (7 values of 7)? Let's count sevens: Positions: 7 (position 2),7 (4),7 (10),7 (12),7 (19),7 (20),7 (21), plus any other7? From original: 15,7,11,7,13,4,8,9,3,7,25,7,6,10,8,9,23,19,7,5,7 Counting sevens: positions 2,4,10,12,19,21 and 20 is 7 or 5? At position 20 is 5, position 21 is 7 So total 7s = 7 occurrences So, sorted data: 3,4,5,6,7,7,7,7,7,7,7,8,8,9,9,10,11,13,15,19,23,25 I'm still counting 22 items here so let's remove the last 25 from the count as data originally has 21 values. The original list of marks is: 15,7,11,7,13,4,8,9,3,7,25,7,6,10,8,9,23,19,7,5,7 Count = 21 marks Sorted list: 3,4,5,6,7,7,7,7,7,7,7,7 (8 sevens?), 8,8,9,9,10,11,13,15,19,23,25 Actually 8 sevens. Positions of sevens: index at original: 2,4,10,12,19,21 & 20 is 5 Only 7 sevens: Count sevens: 7 at positions 2,4,10,12,19,21 (6 sevens), plus one at postion 20 is 7? Check original: 15 (1),7(2),11(3),7(4),13(5),4(6),8(7),9(8),3(9),7(10),25(11),7(12),6(13),10(14),8(15),9(16),23(17),19(18),7(19),5(20),7(21) Sevens at positions 2,4,10,12,19,21 (6 sevens), and position?? position 20 is 5. So 6 sevens total. Hence sorted data: 3,4,5,6,7,7,7,7,7,7,8,8,9,9,10,11,13,15,19,23,25 Count elements: 3(1),4(2),5(3),6(4),7(5),7(6),7(7),7(8),7(9),7(10),8(11),8(12),9(13),9(14),10(15),11(16),13(17),15(18),19(19),23(20),25(21) Wait, here 7 is repeated 6 times (positions 5 to 10), so total 6 sevens correct. Number of elements = 21 The median is the middle value (11th value after sorting): The 11th value is $8$ Step 3: Calculate the mode. Mode is the most frequent value. 7 occurs 6 times, more than any other number. Therefore, mode = 7 3. **Can Thato, who scored 9, claim that his mark is in the top half of the class?** Step 1: Find the median (middle mark) to split the class into two halves. Median = 8 (from previous step) Step 2: Check Thato's mark 9 against median. Since 9 > 8, Thato's mark is higher than the median, meaning his mark falls in the top half of the class. Step 3: Conclude: Thato can claim his mark is in the top half because his score is above the median. 4. **Number of foreign visitors recorded at Rhino Game Park:** Data: 45, 23, 86, 91, 42, 50, 12, 84, 47, 45, 22, 95, 39, 78, 69 This data is simply listed; no further calculations requested. ----- Final answers: - Range = 22 - Mean = 9.33 - Median = 8 - Mode = 7 - Thato's mark of 9 is in the top half of the class because it is greater than the median.