1. **Problem Statement:** Calculate the expected value $E(X)$ and the standard deviation $\sigma$ for a binomial random variable $X$ with parameters $n=10$ and $p=0.94$. 2. **Formulas Used:** - Expected value: $$E(X) = np$$ - Standard deviation: $$\sigma = \sqrt{np(1-p)}$$ 3. **Calculate Expected Value:** Substitute $n=10$ and $p=0.94$ into the formula: $$E(X) = 10 \times 0.94 = 9.4$$ This means on average, we expect 9.4 successes out of 10 trials. 4. **Calculate Standard Deviation:** Substitute $n=10$ and $p=0.94$: $$\sigma = \sqrt{10 \times 0.94 \times (1 - 0.94)} = \sqrt{10 \times 0.94 \times 0.06} = \sqrt{0.564} \approx 0.75$$ The standard deviation measures the variability around the expected value. 5. **Rounding:** Both answers are already rounded to two decimal places. **Final answers:** - (a) Expected value $E(X) = 9.4$ - (b) Standard deviation $\sigma = 0.75$