Binomial Distribution
1. **Problem Statement:** We are given that 83% of federal government employees use e-mail. From a sample of 210 employees, we need to find the mean, variance, and standard deviation of the number who use e-mail.
2. **Relevant Formulas for Binomial Distribution:**
- Mean (expected value): $$\mu = n \times p$$
- Variance: $$\sigma^2 = n \times p \times (1-p)$$
- Standard deviation: $$\sigma = \sqrt{\sigma^2}$$
3. **Given Values:**
- Number of trials (employees): $$n = 210$$
- Probability of success (using e-mail): $$p = 0.83$$
4. **Calculate the Mean:**
$$\mu = 210 \times 0.83 = 174.3$$
5. **Calculate the Variance:**
$$\sigma^2 = 210 \times 0.83 \times (1 - 0.83) = 210 \times 0.83 \times 0.17$$
$$\sigma^2 = 29.601$$
6. **Calculate the Standard Deviation:**
$$\sigma = \sqrt{29.601} \approx 5.441$$
**Final answers:**
- Mean: 174.3
- Variance: 29.601
- Standard deviation: 5.441
These values describe the expected number of employees using e-mail and the variability around that expectation in the sample of 210 employees.