1. The problem asks for the area under the standard normal curve to the right of $z = -2.34$. 2. The standard normal distribution is symmetric about zero, and the total area under the curve is 1. 3. The area to the right of a $z$-value is $1 - P(Z \leq z)$, where $P(Z \leq z)$ is the cumulative probability to the left of $z$. 4. Using standard normal distribution tables or a calculator, find $P(Z \leq -2.34) \approx 0.0096$. 5. Therefore, the area to the right of $z = -2.34$ is: $$ 1 - 0.0096 = 0.9904 $$ 6. This means about 99.04% of the distribution lies to the right of $z = -2.34$. Final answer: $0.9904$