Anova Table
1. **State the assumptions for a valid ANOVA and how to check them:**
- Assumption 1: Independence of observations. Check by ensuring random sampling and experimental design.
- Assumption 2: Normality of residuals. Check using normal probability plots or Shapiro-Wilk test on residuals.
- Assumption 3: Homogeneity of variances (equal variances among groups). Check using Levene's test or Bartlett's test.
2. **Two reasons for running an experiment in blocks:**
- To reduce variability caused by known nuisance factors by grouping similar experimental units.
- To increase precision of treatment comparisons by removing block-to-block variability.
3. **Definitions and importance:**
- Randomization: Assigning experimental units to treatments randomly to avoid bias and confounding.
- Blocking: Grouping similar experimental units (blocks) to control variability from nuisance factors.
- Replication: Repeating treatments on multiple experimental units to estimate experimental error and increase reliability.
4. **Complete the ANOVA table and answer subquestions:**
Given:
- DF(Treatments) = 4, SS(Treatments) = 14.2
- SS(Blocks) = 18.9, DF(Error) = 24
- DF(Total) = 34, SS(Total) = 41.9
Calculate missing degrees of freedom:
$$DF_{Blocks} = DF_{Total} - DF_{Treatments} - DF_{Error} = 34 - 4 - 24 = 6$$
Calculate SS(Error):
$$SS_{Error} = SS_{Total} - SS_{Treatments} - SS_{Blocks} = 41.9 - 14.2 - 18.9 = 8.8$$
Calculate Mean Squares:
$$MS_{Treatments} = \frac{SS_{Treatments}}{DF_{Treatments}} = \frac{14.2}{4} = 3.55$$
$$MS_{Blocks} = \frac{SS_{Blocks}}{DF_{Blocks}} = \frac{18.9}{6} = 3.15$$
$$MS_{Error} = \frac{SS_{Error}}{DF_{Error}} = \frac{8.8}{24} \approx 0.3667$$
Calculate F-values:
$$F_{Treatments} = \frac{MS_{Treatments}}{MS_{Error}} = \frac{3.55}{0.3667} \approx 9.68$$
$$F_{Blocks} = \frac{MS_{Blocks}}{MS_{Error}} = \frac{3.15}{0.3667} \approx 8.59$$
**Answers:**
b. Number of blocks $= DF_{Blocks} + 1 = 6 + 1 = 7$
c. Number of observations $= DF_{Total} + 1 = 34 + 1 = 35$
Since there are 5 treatments ($DF_{Treatments} + 1 = 4 + 1$), observations per treatment:
$$\frac{35}{5} = 7$$
d. Test for treatment differences at $\alpha =0.05$ with $(4,24)$ df:
Critical $F$ from table $\approx 2.78$
Since $F_{Treatments} = 9.68 > 2.78$, reject null hypothesis, treatments differ significantly.
e. Test for block differences at $\alpha=0.05$ with $(6,24)$ df:
Critical $F \approx 2.51$
Since $F_{Blocks} = 8.59 > 2.51$, reject null hypothesis, blocks differ significantly.