Airport Passenger Stats
1. **Problem Statement:** Calculate the mean, median, mode, variance, and standard deviation for the given frequency distribution of passengers (in millions) handled by 20 airports, and interpret these statistics for strategic planning.
2. **Given Data:**
Passengers (millions) | Number of Airports (Frequency, $f$)
10–20 | 6
20–30 | 8
30–40 | 4
40–50 | 2
3. **Step 1: Calculate the midpoints ($x$) of each class interval:**
- 10–20: $\frac{10+20}{2} = 15$
- 20–30: $\frac{20+30}{2} = 25$
- 30–40: $\frac{30+40}{2} = 35$
- 40–50: $\frac{40+50}{2} = 45$
4. **Step 2: Calculate the mean ($\bar{x}$):**
$$\bar{x} = \frac{\sum f x}{\sum f} = \frac{6\times15 + 8\times25 + 4\times35 + 2\times45}{6+8+4+2} = \frac{90 + 200 + 140 + 90}{20} = \frac{520}{20} = 26$$
5. **Step 3: Calculate the median:**
- Total frequency $N=20$
- Median class is where cumulative frequency reaches $\frac{N}{2} = 10$
- Cumulative frequencies: 6, 14, 18, 20
- Median class is 20–30 (since cumulative frequency 14 > 10)
- Use median formula:
$$\text{Median} = L + \left(\frac{\frac{N}{2} - F}{f_m}\right) \times h$$
Where:
$L=20$ (lower boundary of median class),
$F=6$ (cumulative frequency before median class),
$f_m=8$ (frequency of median class),
$h=10$ (class width)
$$\text{Median} = 20 + \left(\frac{10 - 6}{8}\right) \times 10 = 20 + \frac{4}{8} \times 10 = 20 + 5 = 25$$
6. **Step 4: Calculate the mode:**
- Mode class is the class with highest frequency: 20–30 with frequency 8
- Use mode formula:
$$\text{Mode} = L + \frac{(f_1 - f_0)}{(2f_1 - f_0 - f_2)} \times h$$
Where:
$L=20$ (lower boundary of modal class),
$f_1=8$ (frequency of modal class),
$f_0=6$ (frequency before modal class),
$f_2=4$ (frequency after modal class),
$h=10$
$$\text{Mode} = 20 + \frac{8 - 6}{2\times8 - 6 - 4} \times 10 = 20 + \frac{2}{16 - 10} \times 10 = 20 + \frac{2}{6} \times 10 = 20 + 3.33 = 23.33$$
7. **Step 5: Interpret mean, median, and mode:**
- Mean (26 million) represents the average passenger volume.
- Median (25 million) shows the middle value, indicating half the airports handle fewer than 25 million passengers.
- Mode (23.33 million) indicates the most common passenger volume range.
- For strategic planning, these suggest focusing resources around 20–30 million passengers range.
8. **Step 6: Calculate variance ($\sigma^2$) and standard deviation ($\sigma$):**
- Calculate $x^2$ for each midpoint:
$15^2=225$, $25^2=625$, $35^2=1225$, $45^2=2025$
- Calculate $\sum f x^2$:
$$6\times225 + 8\times625 + 4\times1225 + 2\times2025 = 1350 + 5000 + 4900 + 4050 = 15300$$
- Variance formula:
$$\sigma^2 = \frac{\sum f x^2}{N} - \bar{x}^2 = \frac{15300}{20} - 26^2 = 765 - 676 = 89$$
- Standard deviation:
$$\sigma = \sqrt{89} \approx 9.43$$
9. **Step 7: Interpret variance and standard deviation:**
- Variance and standard deviation measure the spread of passenger volumes.
- A standard deviation of 9.43 million indicates moderate variability.
- For risk assessment, this variability suggests some airports have significantly different passenger volumes, affecting resource allocation and operational risk.
**Final answers:**
- Mean = 26 million
- Median = 25 million
- Mode = 23.33 million
- Variance = 89
- Standard deviation $\approx$ 9.43 million
These statistics help the airline plan resource allocation and expansion by focusing on the most common passenger volume ranges and understanding variability for risk management.