1. **Stating the problem:** Calculate the average absolute deviation given three samples and their deviations from the mean. 2. **Formula used:** The absolute deviation for each sample is calculated as $|c_i - \bar{c}|$, where $c_i$ is the sample value and $\bar{c}$ is the mean. 3. **Given values:** - Sample 1 deviation: $|0.104 - 0.098| = 0.006$ - Sample 2 deviation: $|0.097 - 0.09633| = 0.00067$ - Sample 3 deviation: $|0.094 - 0.09633| = 0.00233$ (Note: The first deviation was given as 0.00167 but recalculated correctly as $0.006$) 4. **Calculate the average absolute deviation:** $$\text{Average} = \frac{0.006 + 0.00067 + 0.00233}{3}$$ 5. **Perform the addition:** $$0.006 + 0.00067 + 0.00233 = 0.009$$ 6. **Divide by 3:** $$\frac{0.009}{3} = 0.003$$ 7. **Final answer:** The average absolute deviation is $0.003$. This means on average, the samples deviate from the mean by 0.003 units.