1. **Problem 1:** A ship with a draft at the LCF of 8.0m and a trim by the stern of 0.6m receives an added mass of 200t 30m aft of the LCF. Given \(\Delta = 14000\)t, \(TPC = 16.4\)t/cm, \(MCT1cm = 17\)t-m, and \(LCF\) at midships, we find the new trim and draft. 2. Calculate the initial trim in cm: \[ \text{Initial trim} = 0.6\text{ m} = 60\text{ cm} \] 3. Calculate the change in trim due to added mass: \[ \Delta \text{trim} = \frac{\text{Added moment}}{MCT1cm} = \frac{200\times30}{17} = 352.94\text{ cm} = 3.5294\text{ m} \] (trim by stern increases) 4. Calculate change in draft due to added weight: \[ \Delta \text{draft} = \frac{200}{TPC} = \frac{200}{16.4} = 12.20\text{ cm} = 0.122\text{ m} \] 5. New trim: \[ 0.6 + 3.5294 = 4.1294\text{ m} \] (by stern) 6. New draft at LCF (midships) adding weight: \[ 8.0 + 0.122 = 8.122\text{ m} \] **Answer 1:** New draft = 8.122m, New trim = 4.13m by stern. --- 7. **Problem 2:** A ship load draft is 7m with trim forward (TF) 7.1m and trim aft (TA) 7.5m, given \(\Delta=13,000\)t, \(TPC=15.0\)t/cm, \(MCT1cm=15.5\)t-m, \(LCF=3\)m aft of amidships, \(LBP=150\)m. Find the required load and location to even keel. 8. Calculate the total change in draft: \[ \text{Mean draft} = \frac{7.1 + 7.5}{2} = 7.3\text{ m} \] \[ \Delta \text{draft} = 7.3 - 7 = 0.3\text{ m} = 30\text{ cm} \] 9. Calculate increase in displacement from draft increase: \[ \Delta \text{displacement} = TPC \times \Delta \text{draft (cm)} = 15 \times 30 = 450\text{ t} \] 10. Calculate trim in cm: \[ \text{Trim} = 7.5 - 7.1 = 0.4\text{ m} = 40\text{ cm} \] (trim by stern) 11. Calculate moment to correct trim (even keel): \[ \text{Moment} = \text{Trim} \times MCT1cm = 40 \times 15.5 = 620\text{ t-m} \] 12. Find distance aft of LCF where the load must be added: \[ d = \frac{\text{Moment}}{\Delta \text{displacement}} = \frac{620}{450} = 1.378\text{ m} \text{ aft of LCF} \] 13. Calculate actual position relative to amidships: \[ \text{LCF is 3m aft amidships} \implies \text{Load location} = 3 + 1.378 = 4.378\text{ m aft of amidships} \] **Answer 2:** Required load to add = 450t at 4.38m aft of amidships. --- 14. **Problem 3:** No graphs or mathematical diagrams are visible on the screen, so no calculations or analysis can be performed on graph shapes.