Set Theory
1. Problem A: Set Theory operations and subsets
1.1 Find the subsets of $Q = \{2,4,6\}$.
- The subsets of a set with $n$ elements are $2^n$ in number.
- Here, $n=3$, so total subsets = $2^3 = 8$.
- Subsets are: $\{\}, \{2\}, \{4\}, \{6\}, \{2,4\}, \{2,6\}, \{4,6\}, \{2,4,6\}$.
1.2 Find the proper subsets of $R = \{6,8\}$.
- Proper subsets exclude the set itself.
- Total subsets of $R$ are $2^2=4$.
- Proper subsets are: $\{\}, \{6\}, \{8\}$.
1.3 Find the following sets:
- $P' = U - P = \{0,2,4,6,8\}$
- $Q' = U - Q = \{0,1,3,5,7,8,9\}$
- $P \cup R = \{1,3,5,6,7,8,9\}$
- $P \cap R = \{\}$ (no common elements)
- $P - Q = P$ (since $P$ and $Q$ are disjoint)
2. Problem B: Seminar qualifications
Given:
- Total = 200
- $|B|=115$, $|C|=100$, $|A|=70$
- $|B \cap C|=40$, $|C \cap A|=50$, $|B \cap A|=20$
- None qualified = 10
Find $|B \cap C \cap A|$.
Use inclusion-exclusion:
$$|B \cup C \cup A| = |B| + |C| + |A| - |B \cap C| - |C \cap A| - |B \cap A| + |B \cap C \cap A|$$
Total qualified = $200 - 10 = 190$
So,
$$190 = 115 + 100 + 70 - 40 - 50 - 20 + |B \cap C \cap A|$$
$$190 = 285 - 110 + |B \cap C \cap A|$$
$$190 = 175 + |B \cap C \cap A|$$
$$|B \cap C \cap A| = 190 - 175 = 15$$
3. Problem C: Venn Diagrams sets
Sets given:
- 1) $U=\{1,2,3,4,5,6,7,8,9\}$, $A=\{2,3,5\}$, $B=\{1,4,6,8\}$
- 2) $U=\{1,2,3,4,5,6,7,8,9\}$, $S=\{1,5,7,8,9\}$, $T=\{5,8\}$
- 3) $A=\{1,2,3,7\}$, $B=\{1,2,4,8\}$, $C=\{3,4,5,6\}$
- 4) $U=\{1,2,3,4,5,6,7,8,9\}$, $X=\{1,2,3\}$, $Y=\{1,2,6,7,8,9\}$, $Z=\{4,5,6,7\}$
(These can be represented in separate Venn diagrams with the universal set and the subsets as given.)
4. Problem D: Music exam results
Given:
- $|A|=70$ (vocal test passed)
- $|B|=75$ (instrument test passed)
- $|A \cap B|=55$
4.1 Find number who passed vocal or instrument test:
$$|A \cup B| = |A| + |B| - |A \cap B| = 70 + 75 - 55 = 90$$
4.2 Find number who passed only one test:
- Passed only vocal: $|A| - |A \cap B| = 70 - 55 = 15$
- Passed only instrument: $|B| - |A \cap B| = 75 - 55 = 20$
- Total passed only one test = $15 + 20 = 35$
4.3 Number who failed both tests:
- Total students = 100
- Passed at least one test = 90
- Failed both = $100 - 90 = 10$
5. Problem E: Bank account holders
Given:
- $|A|=325$, $|B|=300$, $|C|=260$
- $|A \cap B|=190$, $|B \cap C|=170$, $|A \cap C|=175$
- Others (not A, B, or C) = 30
- Total = 500
Find $|A \cap B \cap C|$.
Use inclusion-exclusion:
$$|A \cup B \cup C| = |A| + |B| + |C| - |A \cap B| - |B \cap C| - |A \cap C| + |A \cap B \cap C|$$
Since 30 have other accounts, those not in $A \cup B \cup C$ are 30, so:
$$|A \cup B \cup C| = 500 - 30 = 470$$
Substitute:
$$470 = 325 + 300 + 260 - 190 - 170 - 175 + |A \cap B \cap C|$$
$$470 = 885 - 535 + |A \cap B \cap C|$$
$$470 = 350 + |A \cap B \cap C|$$
$$|A \cap B \cap C| = 470 - 350 = 120$$