1. **Problem:** Given sets $A = \{a, b, c, d, e\}$ and $B = \{a, b, c, d, e, f, g, h\}$, find: (a) $A \cup B$ (b) $A \cap B$ (c) $A \setminus B$ (d) $B \setminus A$ 2. **Formulas and rules:** - Union: $A \cup B = \{x | x \in A \text{ or } x \in B\}$ - Intersection: $A \cap B = \{x | x \in A \text{ and } x \in B\}$ - Set difference: $A \setminus B = \{x | x \in A \text{ and } x \notin B\}$ 3. **Step-by-step solution:** (a) $A \cup B$ means all elements in $A$ or $B$ without repetition. Since $B$ contains all elements of $A$ plus $f, g, h$, $$A \cup B = \{a, b, c, d, e, f, g, h\}$$ (b) $A \cap B$ means elements common to both $A$ and $B$. Since $A$ is a subset of $B$, all elements of $A$ are in $B$: $$A \cap B = \{a, b, c, d, e\}$$ (c) $A \setminus B$ means elements in $A$ but not in $B$. Since all elements of $A$ are in $B$, this set is empty: $$A \setminus B = \emptyset$$ (d) $B \setminus A$ means elements in $B$ but not in $A$. These are $f, g, h$: $$B \setminus A = \{f, g, h\}$$ **Final answers:** (a) $\{a, b, c, d, e, f, g, h\}$ (b) $\{a, b, c, d, e\}$ (c) $\emptyset$ (d) $\{f, g, h\}$