Set Operations Ee4D8C
1. Problem: Find the elements and cardinality of $A \cap B$.
Step 1: Identify $A = \{a,b,c,e,f\}$ and $B = \{b,c,d,e,f\}$.
Step 2: Intersection $A \cap B$ contains elements in both $A$ and $B$.
$$A \cap B = \{b,c,e,f\}$$
Step 3: Cardinality $|A \cap B| = 4$.
2. Problem: Find $A' \cup D$ where $A'$ is the complement of $A$ in $U$.
Step 1: Universal set $U = \{a,b,c,d,e,f,g,h,i,j,k\}$.
Step 2: $A' = U - A = \{d,g,h,i,j,k\}$.
Step 3: $D = \{a,e,g,i\}$.
Step 4: Union $A' \cup D = \{a,d,e,g,h,i,j,k\}$.
Step 5: Cardinality $|A' \cup D| = 8$.
3. Problem: Find $(C \cup B)'$.
Step 1: $B = \{b,c,d,e,f\}$, $C = \{f,g,h,k\}$.
Step 2: $C \cup B = \{b,c,d,e,f,g,h,k\}$.
Step 3: Complement $(C \cup B)' = U - (C \cup B) = \{a,i,j\}$.
Step 4: Cardinality $|(C \cup B)'| = 3$.
4. Problem: Find $C \oplus D$ (symmetric difference).
Step 1: $C = \{f,g,h,k\}$, $D = \{a,e,g,i\}$.
Step 2: Symmetric difference is elements in either set but not both.
$$C \oplus D = (C - D) \cup (D - C) = \{f,h,k\} \cup \{a,e,i\} = \{a,e,f,h,i,k\}$$
Step 3: Cardinality $|C \oplus D| = 6$.
5. Problem: Find $A \sim B$ (set difference $A - B$).
Step 1: $A = \{a,b,c,e,f\}$, $B = \{b,c,d,e,f\}$.
Step 2: $A \sim B = \{a\}$ (elements in $A$ not in $B$).
Step 3: Cardinality $|A \sim B| = 1$.
6. Problem: Find $A \cap C'$.
Step 1: $C = \{f,g,h,k\}$, so $C' = U - C = \{a,b,c,d,e,i,j\}$.
Step 2: $A = \{a,b,c,e,f\}$.
Step 3: Intersection $A \cap C' = \{a,b,c,e\}$.
Step 4: Cardinality $|A \cap C'| = 4$.
7. Problem: Find $A \sim U$.
Step 1: $U$ is the universal set, so $A \sim U = A - U = \emptyset$.
Step 2: Cardinality $|A \sim U| = 0$.
8. Problem: Find $(A \oplus B)'$.
Step 1: $A = \{a,b,c,e,f\}$, $B = \{b,c,d,e,f\}$.
Step 2: $A \oplus B = (A - B) \cup (B - A) = \{a\} \cup \{d\} = \{a,d\}$.
Step 3: Complement $(A \oplus B)' = U - \{a,d\} = \{b,c,e,f,g,h,i,j,k\}$.
Step 4: Cardinality $|(A \oplus B)'| = 9$.
9. Problem: Find $(A \cap C) \sim B$.
Step 1: $A = \{a,b,c,e,f\}$, $C = \{f,g,h,k\}$, $B = \{b,c,d,e,f\}$.
Step 2: $A \cap C = \{f\}$.
Step 3: $(A \cap C) \sim B = \{f\} - \{b,c,d,e,f\} = \emptyset$.
Step 4: Cardinality $| (A \cap C) \sim B | = 0$.
10. Problem: Find $(A \sim B) \cap C$.
Step 1: $A \sim B = \{a\}$.
Step 2: $C = \{f,g,h,k\}$.
Step 3: Intersection $\{a\} \cap \{f,g,h,k\} = \emptyset$.
Step 4: Cardinality $| (A \sim B) \cap C | = 0$.
Final answers:
1. $\{b,c,e,f\}, 4$
2. $\{a,d,e,g,h,i,j,k\}, 8$
3. $\{a,i,j\}, 3$
4. $\{a,e,f,h,i,k\}, 6$
5. $\{a\}, 1$
6. $\{a,b,c,e\}, 4$
7. $\emptyset, 0$
8. $\{b,c,e,f,g,h,i,j,k\}, 9$
9. $\emptyset, 0$
10. $\emptyset, 0$