Function Bijective C91D16
1. **Problem Statement:**
(a) Determine which function from the given options is bijective between sets $P = \{10, 20, 30\}$ and $Q = \{5, 10, 15, 20\}$.
2. **Recall:**
A function is **bijective** if it is both **one-to-one (injective)** and **onto (surjective)**.
- **Injective:** Each element of $P$ maps to a unique element in $Q$ (no duplicates in outputs).
- **Surjective:** Every element of $Q$ is mapped by some element in $P$.
3. **Check each function:**
- A: $f = \{(10,5), (10,10), (10,15), (10,20)\}$ maps 10 to multiple values, so not a function.
- B: $f = \{(10,5), (20,10), (30,15)\}$ maps each element of $P$ to a unique element in $Q$. Outputs are $5, 10, 15$.
- C: $f = \{(20,5), (20,10), (30,10)\}$ 20 maps to two values, not a function.
- D: $f = \{(10,5), (10,10), (20,15), (10,20)\}$ 10 maps to multiple values, not a function.
4. **Is B bijective?**
- Injective: Yes, all outputs distinct.
- Surjective: $Q$ has $5, 10, 15, 20$ but $20$ is not mapped, so not onto.
**Conclusion:** None of the given options is bijective.
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**Final answer for (a):** No function listed is bijective.