1. **Problem 10:** Bob needs to mix red, yellow, and white paint in the ratio 5:4:1 to make 750 ml of orange paint. We need to check if Bob has enough paint of each color. 2. The total parts in the ratio are $5 + 4 + 1 = 10$ parts. 3. Each part corresponds to $\frac{750}{10} = 75$ ml. 4. Amounts needed: - Red paint: $5 \times 75 = 375$ ml - Yellow paint: $4 \times 75 = 300$ ml - White paint: $1 \times 75 = 75$ ml 5. Bob has: - Red paint: 400 ml (enough, since 400 > 375) - Yellow paint: 300 ml (exactly enough) - White paint: 200 ml (enough, since 200 > 75) 6. **Answer:** Bob has enough red, yellow, and white paint to make 750 ml of orange paint. --- 7. **Problem 11:** Megan mixes 2 parts fruit juice with 5 parts sparkling water. She has 180 ml fruit juice and 400 ml sparkling water. Find the greatest amount of drink she can make. 8. Total parts = $2 + 5 = 7$ parts. 9. Each part corresponds to the limiting ingredient: - Fruit juice per part: $\frac{180}{2} = 90$ ml - Sparkling water per part: $\frac{400}{5} = 80$ ml 10. The limiting part is 80 ml (sparkling water). 11. Total drink = $7 \times 80 = 560$ ml. 12. **Answer:** Megan can make 560 ml of the drink. --- 13. **Problem 12:** Probability of red counter is 0.35. Blue:white counters ratio is 2:3. Find probabilities of blue and white counters. 14. Total probability = 1. 15. Probability red = 0.35. 16. Let probability blue = $2x$, white = $3x$. 17. Sum: $0.35 + 2x + 3x = 1 \Rightarrow 5x = 0.65 \Rightarrow x = 0.13$. 18. Probability blue = $2 \times 0.13 = 0.26$. 19. Probability white = $3 \times 0.13 = 0.39$. 20. **Answer:** Probability blue = 0.26, white = 0.39. --- 21. **Problem 13:** Al, Tom, Joe share 3000. Al:Tom = 5:4, Joe = 1.5 times Tom. 22. Let Tom's amount = $x$. 23. Al's amount = $\frac{5}{4}x = 1.25x$. 24. Joe's amount = $1.5x$. 25. Total: $1.25x + x + 1.5x = 3.75x = 3000$. 26. Solve for $x$: $x = \frac{3000}{3.75} = 800$. 27. **Answer:** Tom gets 800. --- 28. **Problem 14:** Harry and Gary have 300 stickers. Initial ratio Harry:Gary = 7:3. 29. After giving some stickers, ratio is 8:7. 30. Let initial Harry = $7k$, Gary = $3k$, so $7k + 3k = 300 \Rightarrow 10k = 300 \Rightarrow k = 30$. 31. Initial stickers: Harry = 210, Gary = 90. 32. Let Harry give $x$ stickers to Gary. 33. New amounts: Harry = $210 - x$, Gary = $90 + x$. 34. New ratio: $\frac{210 - x}{90 + x} = \frac{8}{7}$. 35. Cross multiply: $7(210 - x) = 8(90 + x)$. 36. $1470 - 7x = 720 + 8x$. 37. $1470 - 720 = 8x + 7x$. 38. $750 = 15x \Rightarrow x = 50$. 39. **Answer:** Harry gives Gary 50 stickers. --- 40. **Problem 15:** Small bars sold in packs of 4, large bars in packs of 9. 41. Ratio packs small:large = 5:2. 42. Let packs small = $5x$, packs large = $2x$. 43. Total bars: $4 \times 5x + 9 \times 2x = 20x + 18x = 38x$. 44. Given total bars = 190. 45. Solve: $38x = 190 \Rightarrow x = 5$. 46. Number of small bars sold = $4 \times 5x = 4 \times 25 = 100$. 47. **Answer:** 100 small chocolate bars sold. --- 48. **Problem 16:** Dermot has 240 counters: red, blue, yellow, green. 49. Red = 15% of 240 = $0.15 \times 240 = 36$. 50. Blue = $\frac{2}{5} \times 240 = 96$. 51. Yellow:Green = 3:1, total yellow + green = $240 - 36 - 96 = 108$. 52. Let yellow = $3y$, green = $y$, so $3y + y = 4y = 108 \Rightarrow y = 27$. 53. Yellow counters = $3 \times 27 = 81$. 54. **Answer:** Dermot has 81 yellow counters. --- 55. **Problem 17:** Daisy bakes 180 cakes: chocolate, vanilla, banana, lemon. 56. Chocolate = 20% of 180 = $0.2 \times 180 = 36$. 57. Vanilla = $\frac{4}{9} \times 180 = 80$. 58. Banana:Lemon = 3:5. 59. Total banana + lemon = $180 - 36 - 80 = 64$. 60. Let banana = $3z$, lemon = $5z$, so $3z + 5z = 8z = 64 \Rightarrow z = 8$. 61. Lemon cakes = $5 \times 8 = 40$. 62. **Answer:** Daisy has 40 lemon cakes. --- 63. **Problem 18:** Angelina earns 1800 per month, saves 30%, spends 70%. 64. Amount spent = $0.7 \times 1800 = 1260$. 65. Rent : other expenses = 4:5, total parts = 9. 66. Rent = $\frac{4}{9} \times 1260 = 560$. 67. **Answer:** Angelina spends 560 on rent. --- 68. **Problem 19:** Red:Green counters = 2:3, red counters = 28. 69. Let red = $2k = 28 \Rightarrow k = 14$. 70. Total counters = $2k + 3k = 5k = 5 \times 14 = 70$. 71. **Answer:** Total counters = 70. --- 72. **Problem 20:** Clara:Dawn = 5:9, Dawn has 36 more stamps. 73. Let Clara = $5m$, Dawn = $9m$. 74. Difference: $9m - 5m = 4m = 36 \Rightarrow m = 9$. 75. Clara's stamps = $5 \times 9 = 45$. 76. **Answer:** Clara has 45 stamps. --- 77. **Problem 21:** Red:Blue:Yellow = 4:5:8, yellow is 24 more than blue. 78. Let red = $4n$, blue = $5n$, yellow = $8n$. 79. Given: $8n - 5n = 24 \Rightarrow 3n = 24 \Rightarrow n = 8$. 80. Total counters = $4n + 5n + 8n = 17n = 17 \times 8 = 136$. 81. **Answer:** Total counters = 136.