1. We are given four trees with roots and children: top-left tree with root 18 and children 3, 9, 6; top-right tree with root 36 and children 3, 18, 12; bottom-left tree with unknown root and children 36 and 4; bottom-right tree with root 96 and children unknown and 12. 2. Let's analyze the top-left tree: children are 3, 9, 6 and root is 18. Note that 3 + 9 + 6 = 18, so root equals the sum of children. 3. Similarly, top-right tree: children 3 + 18 + 12 = 33, but root is 36, so does not equal sum; However, 3 × 18 × 12 = 648, no simple product. Let's check sum of children + 3 = 36; 33 + 3 = 36, possibly the root equals sum of children plus 3. 4. For bottom-left tree, root unknown, children 36 and 4: If we assume root equals sum of children, root = 36 + 4 = 40. 5. For bottom-right tree, root 96, children unknown and 12: Let the unknown child be x. If root equals sum of children: 96 = x + 12 → x = 96 - 12 = 84. 6. Summary solutions: - Bottom-left root = 40 - Bottom-right left child = 84 Final answers: Bottom-left tree root = $40$ Bottom-right tree left child = $84$