Keyhole Number
1. The problem involves finding a relationship between the numbers in the circular top part and the number in the rectangular bottom part of each keyhole shape.
2. For the first keyhole: numbers are 3, 2, 4 and the bottom number is 75.
3. For the second keyhole: numbers are 3, 5, 4 and the bottom number is 78.
4. Let's analyze possible operations:
- Sum of top numbers for first: $3 + 2 + 4 = 9$
- Product of top numbers for first: $3 \times 2 \times 4 = 24$
- Sum of squares for first: $3^2 + 2^2 + 4^2 = 9 + 4 + 16 = 29$
5. Check these against bottom number 75:
- Try sum multiplied by something: $9 \times 8 + 3 = 75$ (but 9*8=72, +3=75, tried 8 and +3)
6. For the second keyhole:
- Sum: $3 + 5 + 4 = 12$
- Check 12 × 6.5 = 78, exact match.
7. Inconsistent multiplier, try other pattern:
- Check sum of squares for second: $3^2 + 5^2 + 4^2 = 9 + 25 + 16 = 50$ (not close to 78)
- Product: $3 \times 5 \times 4 = 60$
8. Consider sum of products of pairs:
- For first: $(3\times2)+(2\times4)+(3\times4) = 6 + 8 + 12 = 26$, no direct match.
9. Notice difference between bottom and sum of products:
- $75 - 26 = 49 = 7^2$
- $78 - 60 = 18 = 3 \times 6$ no square
10. Hypothesize bottom number = product of top three numbers + square of one number:
- For first: $24 + 7^2$ no matching 7 in numbers.
11. Try sum of first two numbers multiplied by last:
- For first: $(3 + 2) \times 4 = 5 \times 4 = 20$
- For second: $(3 + 5) \times 4 = 8 \times 4 = 32$ no.
12. Check difference between bottom and product:
- First: $75 - 24 = 51$
- Second: $78 - 60 = 18$
- Ratio of differences: 51/18 ≈ 2.83
13. Alternative: sum of numbers squared:
- $(3 + 2 + 4)^2 = 9^2 = 81$ close to 75
- $(3 + 5 + 4)^2 = 12^2 = 144$ not 78
14. Given the inconsistencies, let's assume the bottom number equals $3 \times$ (sum of the first two numbers) plus the third number squared:
- First: $3 \times (3 + 2) + 4^2 = 3 \times 5 + 16 = 15 + 16 = 31$ no.
15. Since the bottom numbers 75 and 78 differ by 3 and the top numbers differ largely, we can guess the bottom number is sum of products plus sum:
- First: $3\times2 + 2\times4 + 3\times4 + 3 + 2 + 4 = 6 + 8 + 12 + 9 = 35$
- No match.
16. For the bottom-left keyhole with numbers 3, 7, 5 and unknown bottom number:
- Calculate product: $3 \times 7 \times 5 = 105$
- Calculate sum: $3 + 7 + 5 = 15$
- Calculate sum of squares: $9 + 49 + 25 = 83$
17. For the bottom-right keyhole with numbers 4, 5, 3 and unknown bottom number:
- Product: $4 \times 5 \times 3 = 60$
- Sum: $4 + 5 + 3 = 12$
- Sum of squares: $16 + 25 + 9 = 50$
18. Notice first bottom number 75 is close to 3 times sum of numbers: $3 \times 9 = 27$, no.
19. Notice first bottom number 75 is close to sum of squares plus product:
- $29 + 24 = 53$ no.
20. Final approach: Observe the bottom number is roughly $3 \times$ sum of top two numbers + $3 \times$ third number:
- For first: $3 \times (3+2) + 3 \times 4 = 15 + 12 = 27$ no.
21. Since no direct pattern emerges easily, assume the bottom number is product of the middle number and a fixed constant plus the sum of the other two:
- For first: middle number = 2, product to get 75 is $(3 + 4) + 2 \times 23 = 7 + 46 = 53$ no.
22. Without an explicit pattern, the best guess for missing numbers is the product of the three numbers:
- Bottom-left missing number: $3 \times 7 \times 5 = 105$
- Bottom-right missing number: $4 \times 5 \times 3 = 60$
**Answer:**
Bottom-left keyhole number is $105$.
Bottom-right keyhole number is $60$.