Diamond Sum
1. Problem: Given the square value 150 and diamond cells 100 (top), 150 (left), 50 (right), 150 (bottom), determine if the values add correctly.
Step 1: The diamond cells represent numbers around the square for addition and subtraction reasoning.
Step 2: Check consistency: sum of two opposite diamonds should equal the square.
Step 3: Check top and bottom: 100 + 150 = 250; this is not equal to the square 150.
Step 4: Check left and right: 150 + 50 = 200; this is not equal to the square 150.
Conclusion: Verify if the problem asks for missing values or validation; here, values donโt sum to the square.
2. Problem: Square is 215; diamond cells top 150, left 200, bottom 150, right empty.
Step 1: Sum of opposite diamonds equal square: top + bottom = 150 + 150 = 300; no match with 215.
Step 2: Left + right = 200 + ? = 215; solve right = 215 - 200 = 15.
Answer: Right diamond cell is 15.
3. Problem: Square empty; all diamond cells 75.
Step 1: Calculate square value as sum of two opposite diamonds: 75 + 75 = 150.
Answer: Square contains 150.
4. Problem: Square empty; diamond cells 125 (top), 125 (left), 150 (right), 200 (bottom).
Step 1: Calculate square as sum of top and bottom: 125 + 200 = 325.
Step 2: Check left and right sum: 125 + 150 = 275.
Step 3: The square value is usually the average or consistent sum; likely square = 325.
Answer: Square contains 325.
5. Problem: Square 75; diamond cells 50 (top), 25 (left), 50 (right), bottom empty.
Step 1: Sum top and bottom = square; 50 + bottom = 75; bottom = 75 - 50 = 25.
Step 2: Sum left and right = square; 25 + 50 = 75; consistent.
Answer: Bottom diamond cell is 25.
6. Problem: Square 105; diamond cells 15 (top), empty (left), 75 (right), 75 (bottom).
Step 1: Sum top and bottom = 15 + 75 = 90; should equal square 105, no.
Step 2: Sum left and right = left + 75 = 105; left = 105 - 75 = 30.
Answer: Left diamond cell is 30.
Final answers:
1. Values inconsistent as given.
2. Right diamond = 15.
3. Square = 150.
4. Square = 325.
5. Bottom diamond = 25.
6. Left diamond = 30.