1. **Stating the problem:** Calculate the average score of students based on their scores in two subjects, then find which students have an average score higher than the overall average. 2. Given: - Number of students $N=7$ - List of student names $FIO=[\text{'Ivanova'}, \text{'Petrova'}, \text{'Sidorova'}, \text{'Kuznetsova'}, \text{'Fedorov'}, \text{'Golubev'}]$ - Scores in subject 1 $subject1=[21,95,35,27,46,78,59]$ - Scores in subject 2 $subject2=[81,10,69,76,45,92,50]$ 3. **Calculate the total sum of all scores:** $$\text{sum_value} = \sum_{i=1}^{N} (subject1_i + subject2_i)$$ Calculate each pair sum: $$(21+81) + (95+10) + (35+69) + (27+76) + (46+45) + (78+92) + (59+50)$$ $$= 102 + 105 + 104 + 103 + 91 + 170 + 109 = 784$$ 4. **Calculate the average score over all students and both subjects:** $$average\_score = \frac{784}{7 \times 2} = \frac{784}{14} = 56$$ 5. **Find students whose average score is above the overall average $56$:** Calculate each student's average: - Ivanova: $\frac{21+81}{2} = 51$ (below 56) - Petrova: $\frac{95+10}{2} = 52.5$ (below 56) - Sidorova: $\frac{35+69}{2} = 52$ (below 56) - Kuznetsova: $\frac{27+76}{2} = 51.5$ (below 56) - Fedorov: $\frac{46+45}{2} = 45.5$ (below 56) - Golubev: $\frac{78+92}{2} = 85$ (above 56) - Missing 7th student's name but scores (59, 50): $\frac{59+50}{2} = 54.5$ (below 56) 6. **Result:** Only Golubev has an average score higher than the overall average. 7. **Final dictionary of students with above-average scores:** $$\text{result} = \{\text{'Golubev'}: 85\}$$