1. **State the problem:** We need to find the probability that the spinner lands on section D given the probabilities for sections A, B, and C. 2. **List the given probabilities:** - Section A: $\frac{1}{20} = 0.05$ - Section B: $0.16$ - Section C: $34\% = 0.34$ 3. **Recall that the total probability must sum to 1:** $$P(A) + P(B) + P(C) + P(D) = 1$$ 4. **Sum the known probabilities:** $$0.05 + 0.16 + 0.34 = 0.55$$ 5. **Calculate the probability of section D:** $$P(D) = 1 - 0.55 = 0.45$$ 6. **Convert probability of D to percentage:** $$0.45 \times 100 = 45\%$$ **Final answer:** The probability of the spinner landing on section D is $\boxed{45\%}$.