Smoking Habit 3F2D85
1. **Stating the problem:** We have a survey of 1000 students at University ABC, with 750 boys and 250 girls. Among smokers, 22.9% are boys and 4.5% are girls. We need to construct a tree diagram illustrating these events.
2. **Understanding the problem:** The tree diagram will show the breakdown of students by gender first, then by smoking status within each gender.
3. **Step 1: Define events and probabilities.**
- Total students: 1000
- Boys: 750 (probability $P(B) = \frac{750}{1000} = 0.75$)
- Girls: 250 (probability $P(G) = \frac{250}{1000} = 0.25$)
4. **Step 2: Smoking percentages among boys and girls.**
- Percentage of smokers who are boys: 22.9%
- Percentage of smokers who are girls: 4.5%
5. **Step 3: Calculate total smokers percentage.**
- Total smokers percentage = $22.9\% + 4.5\% = 27.4\%$
6. **Step 4: Calculate probability of smoking given gender.**
- Probability a student is a smoker: $P(S) = 0.274$
- Probability a smoker is a boy: $P(B|S) = 0.229 / 0.274 \approx 0.836$ (not needed for tree but useful)
7. **Step 5: Calculate smoking rates within boys and girls.**
- Number of smokers who are boys: $229$ (22.9% of 1000)
- Number of boys: 750
- Probability a boy smokes: $P(S|B) = \frac{229}{750} \approx 0.3053$
- Number of smokers who are girls: $45$ (4.5% of 1000)
- Number of girls: 250
- Probability a girl smokes: $P(S|G) = \frac{45}{250} = 0.18$
8. **Step 6: Construct the tree diagram structure:**
- First branch: Gender with probabilities $P(B) = 0.75$, $P(G) = 0.25$
- Second branch: Smoking status given gender:
- For boys: $P(S|B) = 0.3053$, $P(\text{non-smoker}|B) = 1 - 0.3053 = 0.6947$
- For girls: $P(S|G) = 0.18$, $P(\text{non-smoker}|G) = 0.82$
9. **Summary:** The tree diagram starts with gender split, then each gender splits into smoker and non-smoker with the above probabilities.
This completes the construction of the tree diagram illustrating the events.