Seat Probability 7614Df
1. **Problem Statement:** We need to find the probability of being allocated certain types of seats on an airplane given the layout and which seats are occupied.
2. **Understanding Probability:** Probability of an event = \( \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \).
3. **Step 1: Identify total unoccupied seats.**
- Count all unoccupied seats from the layout (not provided explicitly, so assume total unoccupied seats = $N$).
4. **Step 2: Calculate probability for each seat type:**
**i) Front row seat:**
- Count unoccupied seats in the front row = $F$.
- Probability = $\frac{F}{N}$.
**ii) Emergency row seat:**
- Count unoccupied seats in the emergency row = $E$.
- Probability = $\frac{E}{N}$.
**iii) Window seat:**
- Count unoccupied window seats = $W$.
- Probability = $\frac{W}{N}$.
**iv) Aisle seat:**
- Count unoccupied aisle seats = $A$.
- Probability = $\frac{A}{N}$.
5. **Summary:**
- The probability for each seat type is the ratio of unoccupied seats of that type to the total unoccupied seats.
Since the exact seat counts are not provided, the formula for each probability is:
$$\text{Probability} = \frac{\text{Number of unoccupied seats of the type}}{\text{Total unoccupied seats}}$$
This approach helps you calculate the probability once you know the counts from the layout.