1. **State the problem:** We have a lecture hall with 190 seats, 27 of which have left-handed arm tablets. The average class size is 179 students, and 12% of these students are left-handed. We want to find the probability that a right-handed student is forced to use a left-handed arm tablet. 2. **Identify given data:** - Total seats: 190 - Left-handed arm tablets: 27 - Average class size: 179 - Percentage of left-handed students: 12% or 0.12 3. **Calculate the number of left-handed and right-handed students:** - Number of left-handed students: $179 \times 0.12 = 21.48 \approx 21$ - Number of right-handed students: $179 - 21 = 158$ 4. **Calculate the number of right-handed arm tablets:** - Total arm tablets: 190 - Left-handed arm tablets: 27 - Right-handed arm tablets: $190 - 27 = 163$ 5. **Determine if right-handed students are forced to use left-handed tablets:** - Right-handed students: 158 - Right-handed arm tablets: 163 Since there are more right-handed arm tablets (163) than right-handed students (158), no right-handed student needs to use a left-handed tablet. Therefore, the probability is 0. 6. **Final answer:** The probability that a right-handed student is forced to use a left-handed arm tablet is $$0.0000$$