1. **Problem:** Find the probability that a randomly chosen fisherman was fishing far from shore and caught bangus. 2. **Formula:** Probability of an event = \( \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \) 3. **Given:** Number of fishermen fishing far from shore and caught bangus = 18 Total fishermen = 50 4. **Calculation:** $$P(\text{Far from shore and caught bangus}) = \frac{18}{50} = \frac{9}{25} = 0.36$$ 5. **Answer:** The probability is \(0.36\) or 36%. --- 1. **Problem:** Find the probability that a randomly selected participant is female. 2. **Given:** Number of female participants = 35 Total participants = 70 3. **Calculation:** $$P(\text{Female}) = \frac{35}{70} = \frac{1}{2} = 0.5$$ 4. **Answer:** The probability is \(0.5\) or 50%. --- 1. **Problem:** Find the probability that a randomly chosen team is from Tanza 1 given that it won. 2. **Formula:** Conditional probability \(P(A|B) = \frac{P(A \cap B)}{P(B)}\) 3. **Given:** Number of teams from Tanza 1 that won = 8 Total teams that won = 14 4. **Calculation:** $$P(\text{Tanza 1} | \text{Won}) = \frac{8}{14} = \frac{4}{7} \approx 0.5714$$ 5. **Answer:** The probability is approximately \(0.5714\) or 57.14%. --- 1. **Problem:** Find the probability that a randomly chosen volunteer is a student or collected plastic waste. 2. **Formula:** For two events A and B, \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\) 3. **Given:** - Number of students = 40 - Number who collected plastic waste = 45 - Number of students who collected plastic waste = 25 - Total volunteers = 70 4. **Calculation:** $$P(\text{Student}) = \frac{40}{70} = \frac{4}{7}$$ $$P(\text{Plastic Waste}) = \frac{45}{70} = \frac{9}{14}$$ $$P(\text{Student and Plastic Waste}) = \frac{25}{70} = \frac{5}{14}$$ $$P(\text{Student or Plastic Waste}) = \frac{4}{7} + \frac{9}{14} - \frac{5}{14} = \frac{8}{14} + \frac{9}{14} - \frac{5}{14} = \frac{12}{14} = \frac{6}{7} \approx 0.8571$$ 5. **Answer:** The probability is approximately \(0.8571\) or 85.71%.