1. The problem asks for the probability of getting exactly two correct answers out of 4 True or False questions by guessing. 2. Each question has 2 possible answers, so the probability of guessing one question correctly is $\frac{1}{2}$. 3. The number of ways to choose exactly 2 correct answers out of 4 is given by the binomial coefficient $\binom{4}{2}$. 4. The binomial probability formula is: $$P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}$$ where $n=4$, $k=2$, and $p=\frac{1}{2}$. 5. Calculate $\binom{4}{2} = \frac{4!}{2! (4-2)!} = \frac{24}{2 \times 2} = 6$. 6. Calculate the probability: $$P(X=2) = 6 \times \left(\frac{1}{2}\right)^2 \times \left(\frac{1}{2}\right)^{4-2} = 6 \times \frac{1}{4} \times \frac{1}{4} = 6 \times \frac{1}{16} = \frac{6}{16} = 0.375$$ 7. Therefore, the probability of getting exactly two correct answers by guessing is 0.375.