1. The problem is to find the probability of selecting exactly 10 people out of 100. 2. Assuming each person is equally likely to be chosen and the selection is random without replacement, this is a combination problem. 3. The total number of ways to choose 10 people from 100 is given by the binomial coefficient $$\binom{100}{10} = \frac{100!}{10!(100-10)!}$$. 4. If the question is about the probability of selecting a specific group of 10 people, the probability is $$\frac{1}{\binom{100}{10}}$$ because there is only one such group. 5. If the question is about the probability of selecting any 10 people, it depends on the context (e.g., if each person has a probability $p$ of being chosen independently, then it is a binomial probability). 6. For example, if each person is chosen independently with probability $p$, the probability of exactly 10 people being chosen is $$P(X=10) = \binom{100}{10} p^{10} (1-p)^{90}$$. 7. Without additional information about the selection process or probability $p$, the exact probability cannot be determined. Final answer depends on the context: if choosing exactly 10 people out of 100 with equal likelihood, the number of ways is $$\binom{100}{10}$$ and the probability of one specific group is $$\frac{1}{\binom{100}{10}}$$.