1. **Problem Statement:** We have two boxes: Box 1 contains numbers 3, 5, 8 and Box 2 contains numbers 4, 7. One slip is taken from each box. We need to: a) List all possible pairs formed by taking one number from each box. b) Find the probability that both numbers in the pair are odd. c) Find the probability that one number is odd and the other is even. 2. **Step a: List all possible pairs** Each pair consists of one number from Box 1 and one from Box 2. Box 1 numbers: 3, 5, 8 Box 2 numbers: 4, 7 Possible pairs: - (3,4) - (3,7) - (5,4) - (5,7) - (8,4) - (8,7) 3. **Step b: Probability both numbers are odd** Odd numbers in Box 1: 3, 5 Odd numbers in Box 2: 7 Number of favorable pairs where both are odd: - (3,7) - (5,7) Total favorable pairs = 2 Total possible pairs = 6 (from step a) Probability = \frac{\text{favorable pairs}}{\text{total pairs}} = \frac{2}{6} = \frac{1}{3} 4. **Step c: Probability one number is odd and the other is even** Odd numbers in Box 1: 3, 5 Even numbers in Box 1: 8 Odd numbers in Box 2: 7 Even numbers in Box 2: 4 Pairs with one odd and one even: - Odd from Box 1 and Even from Box 2: (3,4), (5,4) - Even from Box 1 and Odd from Box 2: (8,7) Total favorable pairs = 3 Probability = \frac{3}{6} = \frac{1}{2} **Final answers:** - a) Possible pairs: (3,4), (3,7), (5,4), (5,7), (8,4), (8,7) - b) Probability both odd = $\frac{1}{3}$ - c) Probability one odd and one even = $\frac{1}{2}$