1. **State the problem:** We roll a 6-sided die and want to find the probability that the outcome is greater than 2. 2. **Formula:** Probability of an event $E$ is given by $$P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$$ 3. **Identify favorable outcomes:** The die has faces numbered 1 through 6. Outcomes greater than 2 are 3, 4, 5, and 6. 4. **Count favorable outcomes:** There are 4 favorable outcomes. 5. **Count total outcomes:** There are 6 possible outcomes (1, 2, 3, 4, 5, 6). 6. **Calculate probability:** $$P(>2) = \frac{4}{6} = \frac{2}{3} \approx 0.6667$$ 7. **Convert to percentage:** $$0.6667 \times 100 = 66.67\%$$ 8. **Round to nearest tenth:** $$66.7\%$$ **Final answer:** The probability that the die roll is greater than 2 is **66.7%**.