1. Problem statement: We have two families with the following members: - Keluarga Aizat: 13 males and 9 females - Keluarga Deeva: 14 males and 6 females Two people are randomly selected from the combined families. Calculate the probability that the two selected persons include one male and one female. 2. Total members in the combined families: $$13 + 9 + 14 + 6 = 42$$ 3. Total ways to select 2 people from 42: $$\binom{42}{2} = \frac{42 \times 41}{2} = 861$$ 4. Number of males in total: $$13 + 14 = 27$$ Number of females in total: $$9 + 6 = 15$$ 5. Number of favorable outcomes: Selecting one male and one female: $$27 \times 15 = 405$$ 6. Probability of selecting one male and one female: $$\frac{405}{861} = \frac{135}{287} \approx 0.4707$$ Final answer: The probability that one male and one female are selected is $$\frac{135}{287} \approx 0.471$$.