1. **State the problem:** We have two boxes with items, some faulty and some not. We want to find probabilities related to selecting faulty or non-faulty items. 2. **Recall the probability formula:** $$\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$$ 3. **First box:** - Total items = 200 - Faulty items = 25 - Non-faulty items = 200 - 25 = 175 4. **Probability that the selected item from the first box is not faulty:** $$P(\text{not faulty from first box}) = \frac{175}{200} = \frac{7}{8} = 0.875$$ 5. **Second box:** - Total items = 1000 - Faulty items = 100 - Non-faulty items = 1000 - 100 = 900 6. **(i) Probability that the selected item from the second box is faulty:** $$P(\text{faulty from second box}) = \frac{100}{1000} = \frac{1}{10} = 0.1$$ 7. **(ii) Probability that both items (one from each box) are not faulty:** Since the selections are independent, multiply the probabilities: $$P(\text{not faulty from first box}) \times P(\text{not faulty from second box}) = \frac{7}{8} \times \frac{900}{1000} = \frac{7}{8} \times \frac{9}{10} = \frac{63}{80} = 0.7875$$ **Final answers:** - Probability selected item from first box is not faulty: $0.875$ - (i) Probability selected item from second box is faulty: $0.1$ - (ii) Probability both items are not faulty: $0.7875$