1. **Problem:** A box contains 5 red balls, 4 blue balls, and 3 green balls. Two balls are drawn at random. Find the probability that both balls are red or both balls are blue. 2. **Step 1:** Calculate total number of balls: $$5 + 4 + 3 = 12$$. 3. **Step 2:** Calculate total ways to draw 2 balls from 12: $$\binom{12}{2} = \frac{12 \times 11}{2} = 66$$. 4. **Step 3:** Calculate ways to draw 2 red balls: $$\binom{5}{2} = \frac{5 \times 4}{2} = 10$$. 5. **Step 4:** Calculate ways to draw 2 blue balls: $$\binom{4}{2} = \frac{4 \times 3}{2} = 6$$. 6. **Step 5:** Calculate probability both balls are red or both are blue: $$P = \frac{10 + 6}{66} = \frac{16}{66} = \frac{8}{33} \approx 0.2424$$. **Final answer:** The probability that both balls drawn are red or both are blue is $$\frac{8}{33}$$ or approximately 0.2424. **Note:** The second question is not solved here as per instructions to solve only the first problem.