1. **State the problem:** We want to find the probability of hitting the target at least once when 10 shots are fired independently, and the probability of hitting the target with one shot is 10% or 0.1. 2. **Formula used:** The probability of hitting the target at least once is the complement of the probability of hitting the target zero times (missing all shots). 3. **Calculate the probability of missing all shots:** The probability of missing one shot is $1 - 0.1 = 0.9$. 4. Since shots are independent, the probability of missing all 10 shots is $$0.9^{10}$$. 5. **Calculate the probability of hitting at least once:** This is $$1 - 0.9^{10}$$. 6. **Evaluate:** $$0.9^{10} = 0.3486784401$$ approximately. 7. Therefore, the probability of hitting the target at least once is $$1 - 0.3486784401 = 0.6513215599$$ approximately. **Final answer:** The probability of hitting the target at least once in 10 shots is approximately **0.6513** or 65.13%.